Objectives
At the end of this section you should be able to:
When the point at which a force acts moves, the force is said to have done work.
When the force is constant, the work done is defined as the product of the force and distance moved.
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Consider the example in Figure 3.1, a force F acting at the angle q moves a body from point A to point B.
Figure 3.1: Notation for work done by a force
The distance moved in the direction of the force is given by
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So the work done by the force F is
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Work done = Fs
When the angle is 90 then the work done is zero.
The SI units for work are Joules J (with force, F, in Newton's N and distance, s, in metres m).
How much work is done when a force of 5 kN moves its point of application 600mm in the direction of the force.
Solution
Find the work done in raising 100 kg of water through a vertical distance of 3m.
Solution
The force is the weight of the water, so
Forces in practice will often vary. In these cases Equation 3.1 cannot be used. Consider the case where the force varies as in Figure 3.2
For the thin strip with width ds - shown shaded in Figure 3.2 - the force can be considered constant at F. The work done over the distance ds is then
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This is the area of the shaded strip.
The total work done for distance s is the sum of the areas of all such strips. This is the same as the area under the Force-distance curve.
Figure 3.2: Work done by a variable force
So for a variable force
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In general you must uses some special integration technique to obtain
the area under a curve. Three common techniques are the trapezoidal, mid-ordinate
and Simpson's rule. They are not detailed here but may be found in many
mathematical text book.